1. Identify the IP address class for each of the following...
      
   1. 199.28.154.33
   2. 64.65.211.8
   3. 144.155.26.114

1. Class C
2. Class A
3. Class B

1. Class B addresses always start with the first two bits the same, what are they?
      
2. Class C addresses always start with the first three bits the same, what are they?
    
3. Class D addresses always start with the first four bits the same, what are they?
         
4. Class E addresses always start with the first four bits the same, what are they?

1. Class B addresses, all range from 128 to 191. The lowest number is 10000000. The highest number is 10111111. So all IP addresses in this class start with a 10.
     
2. Class C addresses, all range from 192 to 223. The lowest number is 11000000. The highest number is 11011111. So all IP addresses in this class start with a 110.
     
3. Class D addresses, all range from 224 to 239. The lowest number is 11100000. The highest number is 11101111. So all IP addresses in this class start with a 1110.
     
4. Class E addresses, all range from 240 to 255. The lowest number is 11110000. The highest number is 11111111. So all IP addresses in this class start with a 1111.

1. Can you identify which of the the following IP addresses have been incorrectly matched with a class. 
     
   1. Class B   -->   192.28.2.3
   2. Class E   -->   241.6.200.3
   3. Class C   -->   126.30.115.5
         
2. State the class for each subnet mask given below
     
   1. 255.255.0.0
   2. 255.0.0.0
   3. 255.255.255.0  

1.     
   1. Incorrect -  192.28.2.3 is Class C
   2. Correct -  241.6.200.3 is Class E  
   3. Incorrect -  126.30.115.5 is Class A   
         
2.   
   1. Class B
   2. Class A
   3. Class C

1. Specify the network and broadcast address for each IP address given below
      
   1. 196.64.3.18
   2. 144.128.16.56
   3. 102.200.100.6

1. Network Address:   --> 196.64.3.0
Broadcast Address: --> 196.64.3.255
  
2. Network Address:   --> 144.128.0.0
Broadcast Address: --> 144.128.255.255
  
3. Network Address:   --> 102.0.0.0
Broadcast Address: --> 102.255.255.255

1. Specify the number of bits allowed for the host part of each CIDR network address below and the number of hosts the network can address.
     
   1. 116.54.30.6/27
   2. 221.13.45.77/18

1. 27 bits are for the network address and so 5 bits are left for the hosts. Thus, 25 = 32 host addressess are possible but 2 are unusable, so 30 hosts can be given addresses.
    
2. 18 bits are for the network address and so 14 bits are left for the hosts. Thus, 214 = 16384 host addressess are possible but 2 are unusable, so 16382 hosts can be given addresses.